A simple pendulum ,while oscillating ,rises to a maximum vertical height of 5 cm from its rest position when it reaches to its extreme position on one side.If mass of the bob of the simple pendulum is 500 g and g-10 m s^(-2) find : (i)the total energy of simple pendulum at any instant while oscillating ,and (ii)the velocity of bob at its mean position State the assumption made in your calculation .

A simple pendulum ,while oscillating ,rises to a maximum vertical heig

1.	A simple pendulum ,while oscillating ,rises to a maximum vertical height of 5 cm from its rest position when it reaches to its extreme position on one side.If mass of the bob of the simple pendulum is 500 g and g-10 m s^(-2) find : (i)the total energy of simple pendulum at any instant while oscillating ,and (ii)the velocity of bob at its mean position State the assumption made in your calculation .
Answer» Solution :Given ,h=5 cm =0.05 m,m =500 g=0.5 kg ,g=10 m `s^(-2)` Assumption Lthere is no loss of energy due to air FRICTION . (i)Total energy of simple pendulum =potential energy at its extreme position =mgh =`0.5xx10xx0.05=0.25 J` (ii)KINETIC energy at the MEAN position i.e., `(1)/(2)=mgh` or `V=sqrt(2gh)=sqrt(2xx10xx0.05)=sqrt(1)` =`1MS^(-1)`