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A single electron system has ionization energy ` 1. 118 xx 10^7 J mol^(-1)`. Calculate the number of protons in the nucleus of the system . |
Answer» `I.E.=Z^(2)/n^(2)xx21.69xx10^(-19) J` `(11180xx10^(3))/(6.023xx10^(23))=Z^(2)/1^(2)xx21.69xx10^(-19) " " Ans. Z=3` |
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