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A single which can can be green or red with probability `4/5 and 1/5` respectively, is received by station A and then transmitted to station B. The probability of each station reciving the signal correctly is `3/4.` If the singal received at station B is green, then the probability that original singal was green isA. `3/5`B. `6/7`C. `20/23`D. `9/20` |
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Answer» Correct Answer - C Even G = original signal is green `E_(1)=A` receives the signal correct `E_(2)=B` receives the signal correct E = Signal received by B is green P (Signal received by B is green) `=P(GE_(1)E_(2))+P(GbarE_(1)barE_(2))+P(barGE_(1)barE_(2))+P(barGbarE_(1)E_(2))` `P(E)=(46)/(5xx16)` `P(G//E)(40//5xx16)/(46//5xx16)=20/23` |
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