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A soccer ball is projected at an angle of 60° from the ground.It attains its maximum height in 10s. Considering acceleration due to gravity as g = 10 m/s^2. What is the velocity with which it was projected?(a) 115.5 m/s(b) 117 m/s(c) 120 m/s(d) 11.55 m/sThis question was addressed to me in unit test.This intriguing question comes from Simple Projectile Motion topic in chapter Motion in a Plane of Physics – Class 11

Answer»

The CORRECT option is (a) 115.5 m/s

Explanation: The time for achieving the MAXIMUM height is EQUAL to half of the time of flight. Therefore, the time of flight is 20s. The formula for time of flight is t = 2(v sinθ/g). Here, t = 20, θ = 60°, g = 10. Hence, on SOLVING we will get the initial VELOCITY as 115.5m/s.



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