InterviewSolution
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InterviewSolution
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A solid at temperature `T_(1)` is kept in an evacuated chamber at temperature `T_(2)gtT_(1)` . The rate of increase of temperature of the body is proportional toA. `t_(2)^(4)-t_(1)^(4)`B. `(t_(4)^(2)+273)-(t_(1)^(4)+273)`C. `t_(2)-t_(1)`D. `t_(2)^(2)-t_(1)^(2)` |
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Answer» Correct Answer - C c) As we know that, the rate of cooling is `(dtheta)/(dt) = bA(theta-theta_(0))` where, bA=constant `rArr (dtheta)/(dt) alpha (theta-theta_(0))` Also `-(dT)/(dt) alpha T-T_(0)` where, T=temperature and t=time So, the rate of heat absorbed by cooled body is proportional to `t_(2)-t_(1)`. |
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