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A solution containing `0.85 g` of `ZnCI_(2)` in `125.0g` of water freezes at `-0.23^(@)C`. The apparent degree of dissociation of the salt is: `(k_(f)` for water `= 1.86 K kg mol^(-1)`, atomic mass, `Zn = 65.3` and `CI = 35.5)`A. `0.875 M`B. `1.00M`C. `1.75M`D. `0.975M` |
Answer» Correct Answer - A `M_("resultant") = (M_(1)V_(1)+M_(2)V_(2))/(V_("total"))` `= (0.5 xx 750 + 2xx 250)/(1000)` `= (375 +500)/(1000) = 0.875M` |
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