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A solution containing 10.2 g of glycrine per litre is found to be isotonic with 2% solution of glucose `("molar mass"=180 g mol^(-1))`. Calculate the molar mass of glycrine.A. 91.8 gB. 1198 gC. 83.9 gD. 890.3 g |
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Answer» Correct Answer - A `pi_"glycerine"=pi_"glucose"` `n_1/V_1RT=n_2/V_2RT` `10.2/Mxx1/1=2/180xx1000/100 ` `rArr M=(10.2xx18)/2=91.8 g ` (Density of water = `1 g//cm^3`) |
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