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A solution containing `10 g per dm^(3)` of urea (mol.wt. `= 60 g mol^(-1)`) is isotonic with a `5%` ( mass//vol.) of a non-volatile solute. The molecular mass of non-volatile solute is:A. `"250 g mol"^(-1)`B. `"300 g mol"^(-1)`C. `"350 g mol"^(-1)`D. `"200 g mol"^(-1)` |
Answer» Correct Answer - B `pi_(1)` (urea) = `pi_(2)` (unknown solute) `C_(1)` (urea) = `C_(2)` (unknown solute) `[(w_(B)xx1000)/(m_(B)xxV)]_("urea")=[(w_(B)xx1000)/(m_(B)xxV)]_("unknown solute")` `(10xx1000)/(60xx1000)=(5xx1000)/(m_(B)xx100)` `m_(B)=300 "g mol"^(-1)`] |
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