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A solution containing 18 g of anon-volitile solute in 200 g of waer freezes at 272.07 K. Calculate the molecular mass of the solute. (Given `K_(f)`=1.86 K/m)

Answer» Correct Answer - 180 g `mol^(-1)`
`W_(B)=18g, W_(A)=0.2Kg, K_(f)=1.86," K kg mol"^(-1), T_(f)=273 K, T_(f)=272.07 K`
`DeltaT_(f)=T_(f)^(@)-T_(f)=273-272.07=0.93 K, M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))xx(18g))/((0.93K)xx(0.2 Kg))=180" g mol"^(-1).`


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