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A solution contains 0.8960 g of K2SO4 in 500 ml solution. Its osmotic pressure is found to be 0.690 atm at 27°C. calculate the value of vant hoff factor. |
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Answer» MB = WB RT/ ∏ V WB = 0.8960 g V = 500 ml pA0 = 0.5 L R = 0.082 L atm K-1 mol-1 ∏ = 0.69 atm T = 300 K M = 0.896 g x 0.082 L atm K-1 mol-1 x 300 K = 0.69 atm x 0.5 L = 63.9 g mol-1 Normal molar mass = 2 x 39 + 32 + 4 x 32 = 174 g mol-1 molar mass/ Observed molar mass = 174 g mol-1 = 2.72 = 63.9 g mol-1 |
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