1.

A solution contaning 18 g of non-volatile solute in 200 g of water freezes at 272.07 K . Calculate the molecular mass of solute?

Answer»

∆ Tf = 273-272.07 =0.93

∆ Tf = (Kf x WB )/(MB x WA) x1000

 0.93 = (1.86 x 18 )/ (MB x 200)x1000

MB =  180 g mol-1



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