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A solution has `1:4` mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at `20^@C`are `440` mmHgfor pentane and `120`mmHg for hexane .The moleA. `0.786`B. `0.478`C. `0.549`D. `0.200` |
Answer» Correct Answer - B `P=P_(C_(5)H_(12))^(O)xxX_(C_(5)H_(12))+P_(C_(6)H_(14))^(O)xxX_(C_(6)H_(14)),` `p=440xx(1)/(5)+120xx(4)/(5)=(920)/(5)=184 y_(C_(5)H_(12))=(P_(C_(5)H_(12)))/(P_(t))` Now,`Y_(C_(5)H_(12))=(88)/(184)=0.478` |
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