1.

A solution has been prepared by dissolving 5 g of urea in 95 g of water. What is the mass percent of urea in the solution ?

Answer» Mass precent `(Mass %) =(Mass of solute)/(Mass os solution)xx100`
M of urea = fg, Mass of water=95g
Mass percent of urea=`((5g))/((5g+95g))xx100=5%`


Discussion

No Comment Found

Related InterviewSolutions