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A solution has been prepared by dissolving 5 g of urea in 95 g of water. What is the mass percent of urea in the solution ? |
Answer» Mass precent `(Mass %) =(Mass of solute)/(Mass os solution)xx100` M of urea = fg, Mass of water=95g Mass percent of urea=`((5g))/((5g+95g))xx100=5%` |
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