1.

A solution has been prepared by dissolving 60 g of methyI alcogol in 120 g of water. What are the mole freaction of methyI alcohol and water ?

Answer» Correct Answer - 0.220
0.780
`"Moles of"CH_(3)OH=("Mass of" CH_(3)OH)/("Molar mass")=((60g)/(32 g mol^(-1)))=1.875` mol
`"Mass of water"=("Mass of water")/("Molar mass")=((120g)/(18 g mol^(-1)))=6.667` mol
`"Mole fraction of" CH_(2)OH=((1.875"mol"))/((1.874 "mol"+6.667"mol"))=((1.875"mol"))/((8.542"mol"))=0.220`.
Mole fraction of water = 1-0.220 = 0.780.


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