A solution is obtained by mixing 300 g of 25% solution and 400 g of 40

1.	A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate tile mass percentage of the resulting solution.
Answer» 300 g of 25% solution contains solute = 75g 400g of 40% solution contains solute = 160 g Total mass of solute = 160 + 75 = 235 g Total mass oÍ’ solution = 300 + 400 = 700 g % of solute in the final solution = \(\frac{235}{700}\) x 100 = 33.5% % of water in the finaI solution = 100 – 33.5 = 66.5%

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate tile mass percentage of the resulting solution.

Answer»

300 g of 25% solution contains solute = 75g

400g of 40% solution contains solute = 160 g

Total mass of solute = 160 + 75 = 235 g

Total mass oÍ’ solution = 300 + 400 = 700 g

% of solute in the final solution = \(\frac{235}{700}\) x 100 = 33.5%

% of water in the finaI solution = 100 – 33.5 = 66.5%

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A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate tile mass percentage of the resulting solution.

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