InterviewSolution
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InterviewSolution
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A solution is prepared by dissolving 5.64g of flucose in 60g of water. Calculate the following : (i) mass percent of each of glucose and water (ii) molality of the solution (iii) mole fraction of each of glucose and water. |
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Answer» (i) Total mass of solution `=5.64 +60 =65.64g` Mass percent of glucose `= (5.64)/(65.64)xx100 = 8.59%` Mass percent of water = (100 - Mass percent of glucose) `= (100-8.59)=91.41%` (ii) No. of moles of glucose `=(5.64)/(180)` Mass of water in kg `= (60)/(1000)` Molality `= (5.64)/(180)xx(1000)/(60) = 0.522 m` (iii) No. of moles of glucose `= (5.64)/(180)=0.0313` No. of moles of water `= (60)/(18) = 3.333` Mole fraction of glucose `= (0.0313)/(3.333+0.0313) = 0.0093` Mole fraction of water `= (3.333)/(3.333 + 0.0313)=0.9907`. |
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