1.

A solution of 2.5g of non-volatile solid in 100g benzene is boiled at `0.42^(@)C` higher than the boiling point of pure benzene. Calculate the molecular mass of the substance. Molal elevation constant of benzene is `2.67 "K kg mol"^(-1)`.

Answer» `m=(1000K_(b)xxw)/(WxxDeltaT)`
Given, `K_(b)=2.67,w=2.5g,W=100g,DeltaT=0.42`
`m=(1000xx2.67xx2.5)/(100xx0.42)=158.9`
The molecular mass of substance is 158.9.


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