A solution of an organic compound is prepared by dissolving `30 g` in `100 g` water. Calculate the molecular mass of compound and the osmotic pressure of solution at `300 K`, when the elevation in boiling point is `0.52` and `K_(b)` for water is `0.52 K m^(-1)`.

A solution of an organic compound is prepared by dissolving `30 g` in

1.	A solution of an organic compound is prepared by dissolving `30 g` in `100 g` water. Calculate the molecular mass of compound and the osmotic pressure of solution at `300 K`, when the elevation in boiling point is `0.52` and `K_(b)` for water is `0.52 K m^(-1)`.
Answer» The given values are `W_(B)=30 g`,`W_(A)=100 g`,`T=300 K ` `DeltaT_(b)=0.52 K m^(-1)` Now, using formula `Mw_(B)=(K_(f)xx1000xxW_(B))/(W_(A)xxDeltaT_(b))` `=(0.52xx1000xx30)/(100xx0.52)=300 g` For osmotic pressure, `pi=(piRT)/V= W_(B)/Mw_(B)xx(RxxT)/V=30/300xx(0.082xx300)/(100//1000)` =2.45 atm

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A solution of an organic compound is prepared by dissolving `30 g` in `100 g` water. Calculate the molecular mass of compound and the osmotic pressure of solution at `300 K`, when the elevation in boiling point is `0.52` and `K_(b)` for water is `0.52 K m^(-1)`.

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