A solution of cane sugar containing 18 g L-1 has an osmotic pressure 1

1.	A solution of cane sugar containing 18 g L-1 has an osmotic pressure 1.25 atm. Calculate the temperature of the solution.(Molar mass of cane sugar = 342, R = 0.082 lit atm mol-1K-1)
Answer» Given : Amount of cane sugar = W = 18 g L^-1 Osmotic pressure = π = 1.25 atm Molar mass of cane sugar = M = 342 g mol^-1 Temperature = T = ? Number of moles of cane sugar = \(\frac{W}{M}\) = \(\frac{18}{342}\) = 0.05263 mol lit^-1 ∴ Concentration of solution = C = \(\frac{n}{V}\) = \(\frac{0.05263}{1}\) = 0.05263 mol lit^-1 π = CRT ∴ T = \(\frac{\pi}{CR}\) = \(\frac{1.25}{0.05236\times 0.08206}\) = 289.4 K ∴ Temperature of solution = 289.4 K

A solution of cane sugar containing 18 g L-1 has an osmotic pressure 1.25 atm. Calculate the temperature of the solution.(Molar mass of cane sugar = 342, R = 0.082 lit atm mol-1K-1)

Answer»

Given :

Amount of cane sugar = W = 18 g L^-1

Osmotic pressure = π = 1.25 atm

Molar mass of cane sugar = M = 342 g mol^-1

Temperature = T = ?

Number of moles of cane sugar

= \(\frac{W}{M}\)

= \(\frac{18}{342}\)

= 0.05263 mol lit^-1

∴ Concentration of solution = C

= \(\frac{n}{V}\)

= \(\frac{0.05263}{1}\)

= 0.05263 mol lit^-1

π = CRT

∴ T = \(\frac{\pi}{CR}\)

= \(\frac{1.25}{0.05236\times 0.08206}\)

= 289.4 K

∴ Temperature of solution = 289.4 K

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A solution of cane sugar containing 18 g L-1 has an osmotic pressure 1.25 atm. Calculate the temperature of the solution.(Molar mass of cane sugar = 342, R = 0.082 lit atm mol-1K-1)

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