1.

A solution of glucose in water is labelled as `10%` w/w. What would be the molarity of the solution ?

Answer» Given `10%((W)/(w))` glucose in water solution
Weight of glucose = 10 gms
GMW of glucose `(C_(6)H_(12)O_(6))=180`
Weight of water `=100-10=90" gms"`
Molarity (m) `=("Weight")/("GMW")xx(1000)/(W("gms"))` ltbbrgt `=(10)/(180)xx(1000)/(90)=(100)/(18xx9)`
`=0.617" moles"//"kg"`
Molarity `=("Weight")/("GMW")xx(1000)/("V"(ml))`
Weight of solution = 100 gms
Assuming that Density of solution = 1.2 gm/ml
`:." Volume "=(100)/(1.2)=83.33" ml"`
`:." Molarity (M)"=(10)/(180)xx(1000)/(83.33)"ml"`
`=(1000)/(18xx83.33)=0.67" M"`


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