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A solution of glucose in water is labelled as `10%` w/w. What would be the molarity of the solution ? |
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Answer» Given `10%((W)/(w))` glucose in water solution Weight of glucose = 10 gms GMW of glucose `(C_(6)H_(12)O_(6))=180` Weight of water `=100-10=90" gms"` Molarity (m) `=("Weight")/("GMW")xx(1000)/(W("gms"))` ltbbrgt `=(10)/(180)xx(1000)/(90)=(100)/(18xx9)` `=0.617" moles"//"kg"` Molarity `=("Weight")/("GMW")xx(1000)/("V"(ml))` Weight of solution = 100 gms Assuming that Density of solution = 1.2 gm/ml `:." Volume "=(100)/(1.2)=83.33" ml"` `:." Molarity (M)"=(10)/(180)xx(1000)/(83.33)"ml"` `=(1000)/(18xx83.33)=0.67" M"` |
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