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A solution of glycerol `(C_(3)H_(8)O_(3))` with mlar mass =92 g `mol^(-1)` in water was prepared by dissolved some glycerol in 500 g of water. The solution had a boiling point of `100.42^(@)C`. What mas of glycerol was dissolved to prepare this olution (`K_(2)` for water = 0.512 K kg `mol^(-1)`). |
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Answer» Correct Answer - 37.7 g `DeltaT_(b)=(100.42^(@)C-100)^(@)C=0.42^(@)C=0.42" K",` `M_(B)=92" g mol"^(-1),W_(A)=500 g =0.5" kg",` `K_(b)=0.152" k kg mol"^(-1)` `W_(B)=(M_(B)xxDeltaT_(b)xxW_(A))/(K_(b))=((92g mol^(-1))xx(0.42K)xx(0.5kg))/((0.512" k kg mol"^(-1)))=37.7 g`. |
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