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A solution of sucrose (molar mass `= 342 g mol^(-1))` has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be: `(K_(f)` for water `= 1.86 K kg mol^(-1))`A. `-0.520^(@)C`B. `+0.372^(@)C`C. `-0.570^(@)C`D. `-0.372^(@)C` |
Answer» Correct Answer - D Depression in freezing point `DeltaT_(f)=K_(f)xxm` Molality `=(W_(B)xx1000)/(M_(B)xxW_(A))=(68.5xx1000)/(342xx1000)` `=(68.5)/(342)`m `:. DeltaT_(f)=1.86xx(68.5)/(342)=0.372^(@)C` `T_(f)=T_(f)^(@)-DeltaT_(f)=0.0-0.372=00.372^(@)C` . |
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