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A solution of urea in water has boiling point of `100.15^(@)C`. Calculate the freezing point of the same solution if `K_(f)` and `K_(b)` for water are `1.87 K kg mol^(-1)` and `0.52 K kg mol^(-1)`, respectively. |
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Answer» `DeltaT_(b)=(100.15-100)=0.15^(@)C` We know that, `DeltaT_(b)=` molality `xx K_(b)` Molality `= (DeltaT_(b))/(K_(b))=(0.15)/(0.52)=0.2884` `DeltaT_(f)=` molality `xxK_(f)` `=0.02884xx1.87=0.54^(@)C` Thus, the freezing point of the solution `=-0.54^(@)C`. |
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