1.

A source and listener are both moving towards each other with a speed v/10 where v is the speed of sound. If the frequency of the note emitted by the source is f, what will be the frequency heard by the listener?

Answer»

Solution :When SOURCE and listener are both MOVING towards each other, the apparent frequency is
`N.=((V+v_(t))/(v-v_(s)))n`
`n.=((v+(v)/(10))/(v-(v)/(10)))n`
`n.=(11)/(9).F`
`=1.22f`


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