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A source and listener are both moving towards each other with a speed v/10 where v is the speed of sound. If the frequency of the note emitted by the source is f, what will be the frequency heard by the listener? |
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Answer» Solution :When SOURCE and listener are both MOVING towards each other, the apparent frequency is `N.=((V+v_(t))/(v-v_(s)))n` `n.=((v+(v)/(10))/(v-(v)/(10)))n` `n.=(11)/(9).F` `=1.22f` |
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