A source of sound is moving with a velocity of 50ms^(-1) towards a stationary listener. The listener measures the frequency of the source as 1000Hz. What will be the apparent frequency of the source when it is moving away from the listener after crossing him? (velocity of sound in the medium is 330ms^(-1)).

A source of sound is moving with a velocity of 50ms^(-1) towards a sta

1.	A source of sound is moving with a velocity of 50ms^(-1) towards a stationary listener. The listener measures the frequency of the source as 1000Hz. What will be the apparent frequency of the source when it is moving away from the listener after crossing him? (velocity of sound in the medium is 330ms^(-1)).
Answer» Solution :When the source is MOVING TOWARDS the STATIONARY listener, the expression for APPARENT frequency is `n.=((v)/(v-v_(s)))n` `1000=((330)/(330-50))n` `n=((1000xx280)/(330))` `n=848.48Hz` The actual frequency of the sound is 848.48 Hz. When the source is moving away from the stationary listener, the expression for apparent frequency is `n.=((v)/(v-v_(s)))n` `=((30)/(330+50))xx848.48` =736.84Hz`