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A source producing a sound of frequency 90 Hz is approaching a stationary listener with a speed equal to (1/10) of the speed of sound. What will be the frequency heard by the listener? |
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Answer» Solution :When the SOURCE is MOVING towards the STATIONARY listener, the expression for apparent frequency is `N.=((v)/(v-v_(s)))n` `=((v)/(v-((1)/(10))v))n=((10)/(9))n` `=((10)/(9))xx90=100Hz` |
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