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A spar is located at 65% of MAC from leading edge. If spar is positioned in such way that distance between t.e. and spar is 2m then, estimate chord of wing.(a) 5.71m(b) 6.8(c) 4.4(d) 6.5I had been asked this question in unit test.I'd like to ask this question from Configuration Layout topic in chapter Configuration Layout Considerations of Aircraft Design

Answer»

The correct answer is (a) 5.71m

The explanation: Given LOCATION of spar = 65% of MAC, distance from t.e. = 2m.

Spar is LOCATED at 65% of chord from l.e. HENCE, from t.e. location of spar = (100% – 65%) of chord = 1-0.65 = 0.35*chord.

From given, 0.35*chord = 2m

Chord = 2/0.35 = 5.71m.



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