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A spectral line in the spectrum of H atom has a wavelength of `15222.22 cm^(-1)` .The transition responsible for this rediation is (Rydherg constant `R = 10977 cm^(-1)`A. `2 rarr 1`B. `4 rarr 2`C. `5 rarr 2`D. `2 rarr 3` |
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Answer» `lambda = (1)/(bar v) = (1)/(15222.32) = 6.569 xx 10^(-5)cm = 6569 Å`(Visible light wavelength) Clearly it lies in the visible regain i.e. in balmer series Hence `n_(1) = 2` Using the relation for wavelength foir H atom `bar v = (1)/(lambda) = RZ^(2)((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))` `15222.22=109677(1/2^(2)-1/n_(2)^(2))` `n_(1) = 3` THe required transition is `3 rarr 2` gtHence c is correct |
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