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A spring is stretched by a length x, then the potential energy stored in it changes by 0.5*k*x^2, where k is the spring constant.(a) True(b) FalseThe question was posed to me during an interview.Origin of the question is Work Done by a Variable Force topic in chapter Work, Energy and Power of Physics – Class 11 |
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Answer» RIGHT answer is (a) True Explanation: The POTENTIAL energy of a stretched spring is GIVEN by 0.5*k*x^2 where x is the elongation in the spring. |
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