A steel pipe has outer radius equal to 3cm and inner radius equal to 2cm. Its length is equal to 5m. What is the mass of the pipe if one cm^3 of steel is 8.05 gram? (Take π = \(\frac{22}{7}\))(a) 63.25 kg(b) 65 kg(c) 67 kg(d) 61 kgThe question was posed to me in unit test.I'd like to ask this question from Volume of a Cylinder topic in portion Surface Areas and Volumes of Mathematics – Class 9

A steel pipe has outer radius equal to 3cm and inner radius equal to 2

1.	A steel pipe has outer radius equal to 3cm and inner radius equal to 2cm. Its length is equal to 5m. What is the mass of the pipe if one cm^3 of steel is 8.05 gram? (Take π = \(\frac{22}{7}\))(a) 63.25 kg(b) 65 kg(c) 67 kg(d) 61 kgThe question was posed to me in unit test.I'd like to ask this question from Volume of a Cylinder topic in portion Surface Areas and Volumes of Mathematics – Class 9
Answer» Right choice is (a) 63.25 kg The best I can explain: LET the OUTER radius = ro = 3cm Inner radius = ri = 2cm Height (here length) = l = 5M = 500cm Volume of PIPE = π * (ro ^2 – ri ^2) * l = \(\frac{22}{7}\) * (3^2 – 2^2) * 500 = 7857.14cm^3 Mass of 1cm^3 is 8.05 gram Therefore, mass of 7857.14cm^3 is equal to 8.05 * 7857.14 = 63249.97gm ≈ 63250 gm = 63.25 kg.

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