1.

A stone is dropped from the top of a tower 500m height into a pond of water at the base of the tower. When is the splash heard at the top ? Given g=10ms^(-2) and speed ofsound =340m//s.

Answer»



Solution :Height of the tower, `S=500m`.
Velocity of sound , `upsilon=340ms^(-1)`
Acceleration due to GRAVITY, `g=10m//s^(2)`.
Initial velocity of the stone, `u=o` (since the stone is initially at rest)
TIME TAKEN by the stone to fall to the baseof the tower, `t_(2)`
According to the second EQUATION of motion.
`S=ut_(1)+1//2 x 10x t_(1)^(2)`
`t_(1)^(2)=100 "" t_(1)=10S`
Now, time taken by the sound to reachthe TOP from the base of the tower, `t_(2)=500//340=1.47`s
Therefore, the splashis heard at the top after time, t
Where, `t=t_(1)+t_(2)=10+1.47=11.47S`.


Discussion

No Comment Found

Related InterviewSolutions