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A stone is throuwn in a vertically upward direction with a velocity of 5 ms ^(-1). If the acceleration of the stone during its motion is 10 ms ^(-2) in the downword direction, what will be the height attained by the stone and how much time will it take to reach there ? |
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Answer» Solution :Here, `u = 5 ms ^(-1), a =- 10 ms ^(-2)..` (Because the stone is moving in the upward direction). `u =0…` at the highest point. `v + u + at` `THEREFORE 0 = 5 + (1-10)t therefore 10 t =5 therefore t =0.5 sec` The stone will REACH the height of `1.25 m ` and the time required is `0.5 sec. ` |
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