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A stone is thrown upwards with a velocity `50 ms^-1`. Another stone is simultaneously thrown downwards from the same location with a velocity `50 ms^-1`. When the first stone is at the highest point, the velocity of the second stone is `("Take" g = 10^-2)` :A. ZeroB. `50 ms^-1`C. `100 ms^-1`D. `150 ms^-1` |
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Answer» Correct Answer - C `t = (50)/(g) = (50)/(10) = 5 s` `v = -50 - 10 xx 5 = -100 m//s`. |
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