InterviewSolution
Saved Bookmarks
| 1. |
A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s^(2), find the maximum height reached by the the stone. What is the net displacement and the total distance covered by the stone? |
|
Answer» Solution :h = s `V^(2) - U^(2) = `2gs `0^(2) - (40)^(2) = 2 xx (-10) `s s = 80 m Total distance = 80 m + 80 m = 160 m |
|