A stone thrown vertically upwards with initial velocity u reaches a height h before coming down. Show that the time taken to go up is same as the time taken to come down.

A stone thrown vertically upwards with initial velocity u reaches a he

1.	A stone thrown vertically upwards with initial velocity u reaches a height h before coming down. Show that the time taken to go up is same as the time taken to come down.
Answer» Solution :When OBJECT is THROWN up INITIAL velocity `=um//s` Final velocity`=0m//s` Acceleration`==gm//s^(2)` Time taken to go up `=t_(1)` According to 1st EQ.of motion `v=u+"GT"` `0=u-"gt"_(1)` `"gt"_(1)=u` `t_(1)=u/g(s)`.....i when object falls down. Initial velocity `=0m//s` Final velocity `(v)=um//s` Acceleration `=gm//s^(2)` Time taken to go down `=t_(2)` According to 1st eq. of motion `v=u+"gt"` `u=0+"gt"_(2)` `t_(2)=u/t(s)`.........ii `t_(1)=t_(2)`