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| 1. |
A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 seconds, what is the magnitude and direction of acceleration of the stone ? |
| Answer» SOLUTION :`OMEGA=(88)/(25)"rad s"^(-1), omega=(2PI)/(T)=(2pi N)/(t)` | |