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A storage battery contains a solution of `H_(2)SO_(4) 30%` by weight. Find out (Given density of solution`=1.2gm//cm^(3)`)A. MolalityB. MolarityC. NormalityD. Mole fraction of `H_(2)SO_(4)` |
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Answer» 30% by weight `implies W_("solute")=30gm,W_("solution")=100gm,W_("solvent")=70gm` `V_("solution")=100/1.2mL` `n_("solution")=30/98=0.306 " "n_("solvent")=70/18=3.889` (i) Molality`=(n_("solute")xx1000)/w_("solvent")=(0.306xx1000)/70=4.37m` (ii) Molarity`=(n_("solute")xx1000)/V_("solution")=(0.306xx1000)/(100/1.2)=3.67M` (iii)`"Normality" =(w_("solute")xx1000)/(E_("solute")xxV_("solution"))=(30xx1000)/(49xx100/1.2)=7.37N` Alternately `Normality=("n-factor"xx"Molarity")` `=2xx3.67=7.34` (iv)` X_(H_(2)SO_(4))=X_(H_(2)SO_(4))/(n_(H_(2)SO_(4))+n_(H_(2)O))=0.306/(0.306+3.889)=0.07` |
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