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A stream of air is bubbled slowly through liquid benzene in a flask at `20.0^(@)C` against an ambient pressure of `100.56kPa`. After the passage of `4.80L` of air, measured at `20.0^(@)C` and `100.56kPa` before it contains benzonb vapor, it is found that `1.705g` of benzene have been evaporated. Assuming that the air saturated benzene vapor when it leaves the flask. Calculate the equilibrium vapor pressure of the benzene at `20.0^(@)C`. |
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Answer» Correct Answer - `11.08kPa` Volume of Benzene `=4.80 lt` no of moles of Benzene `=(1.705)/(78)` Temperature `=20^(@)C=293K` `(nRT)/(V)=0.109` atm `=11.08 kPa`. |
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