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A student did the experiment to find the equivalent resistance of two given resistors, R_(1) and R_(2) first when they are connected in series and next when they are connected in parallel. The two values of the equivalent resistance obtained by him were R_(s) and R_(p) respectively. Compare R_(s)and R_(p). |
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Answer» SOLUTION :In SERIES, the equivalent RESISTANCE `R_(s)=R_(1)+R_(2)` In PARALLEL, the equivalent resistance `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))` `(1)/(R_(p))=(R_(1)+R_(2))/(R_(1)R_(2))` `R_(p)=(R_(1)R_(2))/(R_(1)+R_(2))` Clearly, `R_(s)gtR_(p)`. |
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