1.

A student was given three resistances of 5 Omega,2 Omega and 3 Omega He experimentally obtained the equivalent resistance of their series combination. The correct value will be:

Answer»

`0.9 Omega`
`10 Omega`
`1.03 Omega`
`10.9 Omega`

Solution :In series ARRANGEMENT NET RESISTANCE `R=R_1+R_2+R_3=5+2+3=10 Omega`


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