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A tent is to be built in the form of a cylinder of radius 7 m surmounted by a cone of the same radius. If the height of the cylindrical part is 8 m and slant height of the conical part is 12 m, how much canvas will be required to build the tent? Allow 20% extra canvas for folding and stitching. (Take π = 22/7)1). 1478.4 sq. m2). 2217.6 sq. m3). 369.6 sq. m4). 739.2 sq. m |
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Answer» AREA of tent = Curved SURFACE area of CYLINDER + Area of cone Curved surface area of cylinder = 2πrh Area of cone = πrl Area of tent = 2πrh + πrl Total area = 2(22/7) × (7) × (8) + (22/7) × (7) × (12) = 616 m2 Canvas required = (120/100) × 616 = 739.2 m2 |
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