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A tower subtends an angle of `30^@` at a point on the same level as its foot. At a second point h metres above the first, the depression of the foot of the tower is `60^@` . The height of the tower is: |
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Answer» With the given details, we can draw the figure. Please refer to video for he figure. In the figure, `CD` is the height of the tower and `A` and `B` are the two given points such that `AB = h` Let `AB = h, BC = y and CD = x` Then, `h/y = tan60^@ => y = h/sqrt3` Also, `x/y = tan 30^@ => x = y/sqrt3` `=> x = (h/sqrt3)/(sqrt3) = h/3` `:. ` Height of the tower is `h/3` metres. |
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