1.

From a point on a cricket ground ,the angle of elevation of the top a lower is found to `30^@` at a distance of 225m from the tower. On walking 150m towards the tower, again the angle of elevation is found Find the new angle of elevation and the height of the tower

Answer» `In/_ABD`
`tan30=(AB)/(BD)=h/225`
`h=225tan30`
`h=225/sqrt3m`
`h=75sqrt3m`
`In/_ABC`
`tantheta=h/75`
`tantheta=sqrt3`
`theta=60`.


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