1.

A train covers 's' distance at the constant speed 30 km h^(-1)Then it covers the same distance in opposite direction at constant speed 45 km h^(-1), then its average speed would be ......... km h ^(-1). (37.5, 36, 25)

Answer»

Solution :AVERAGE speed `= ("Total distance")("Total TIME") = (s +s)/(( s )/(30 ) + (s)/(45)) = (2s )/((s (45 + 30))/(30 xx 45 ))= (2s (30 xx 45))/( s (75)) = (2700)/(75) = 36 km H ^(-1)`


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