A train is running at a speed of 45 km/hr and a man is walking at a sp

1.	A train is running at a speed of 45 km/hr and a man is walking at a speed of 5 km/hr in the opposite direction. If the train crosses the man in 18 seconds, then its length is (a) 200 m (b) 220 m (c) 180 m (d) 250 m
Answer» (d) 250 m Since the man is walking in the opposite direction of the moving train, Relative speed of the train = (45 + 5) km/hr = \(\bigg(50\times\frac{5}{18}\bigg)\) m/sec = \(\frac{250}{18}\) m/sec Length of the train = Relative speed x Time taken in crossing the man = \(\bigg(\frac{250}{18}\times18\bigg)\) m = 250 m.

A train is running at a speed of 45 km/hr and a man is walking at a speed of 5 km/hr in the opposite direction. If the train crosses the man in 18 seconds, then its length is (a) 200 m (b) 220 m (c) 180 m (d) 250 m

Answer»

(d) 250 m

Since the man is walking in the opposite direction of the moving train,

Relative speed of the train = (45 + 5) km/hr

= \(\bigg(50\times\frac{5}{18}\bigg)\) m/sec = \(\frac{250}{18}\) m/sec

Length of the train = Relative speed x Time taken in crossing the man

= \(\bigg(\frac{250}{18}\times18\bigg)\) m = 250 m.

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A train is running at a speed of 45 km/hr and a man is walking at a speed of 5 km/hr in the opposite direction. If the train crosses the man in 18 seconds, then its length is (a) 200 m (b) 220 m (c) 180 m (d) 250 m

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