InterviewSolution
Saved Bookmarks
| 1. |
A train is travelling at a peed of 90 km h ^(-1). Breakes are applied so as to produce a uniform acceleration of - 0.5 ms ^(-2). Find how far the train will go before it is brought to rest. |
|
Answer» Solution :Here, `U = 90 km h ^(-1) =(90 xx 1000)/(3600) = 25 ms ^(-1) ,` `a =- 0.5 ms ^(-2),` `v =0` (Because TH train is brought to REST.) `v ^(2) -u ^(2) = 2 as` `therefore 0- (25) ^(2) =2 xx (-0.5) xx s` `therefore s = (- (25 xx 25))/(- 2 xx 0.5) = 625 m` The tranin will cover a DISTANCE of 625 m before it comes to rest. |
|