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A truck of mass 1000 kg accelerates uniformly from rest to a velocity of 15ms^(-1) in 5 seconds. Calculate (i) its acceleration, (i) its gain in K.E., (iii) average power of the engine during this period, neglect friction. |
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Answer» SOLUTION :(i)`a=(v-u)/t=3m//s^(2)` (II)Gain in K.E.`=1/2m(v^(2)-u^(2))=1.125xx10^(5)J` (iii) `P=W/t=22500W` |
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