A uniform metre rule of mass 100g is balanced on a fulcrum at mark 40cm by suspending an unknown mass m at the mark 20cm. (i) Find the value of m. (ii) To which side the rule will tilt if the mass m is moved to the mark 10cm? (iii) What is the resultant moment now? (iv) How can it be balanced by another mass of 50 g?

A uniform metre rule of mass 100g is balanced on a fulcrum at mark 40c

1.	A uniform metre rule of mass 100g is balanced on a fulcrum at mark 40cm by suspending an unknown mass m at the mark 20cm. (i) Find the value of m. (ii) To which side the rule will tilt if the mass m is moved to the mark 10cm? (iii) What is the resultant moment now? (iv) How can it be balanced by another mass of 50 g?
Answer» SOLUTION :(i) m=50g (ii) on the side of MASS m, (iii) `500gf TIMES cm` (anticlockwise)(iv) by SUSPENDING the mass 50g at the mark 50cm.