1.

A uniform metre scale of weight 20 gf is supported on a wedge placed at 60 cm mark. If a weight of 30 gf issuspended at 15 cm mark, where should a weight 200 gf be suspended inorder to balance the metre scale?

Answer»

Solution : (I) Apply the law of moments.
(ii) Let the weight of 200 gf be suspended at distance 'x'.
(iii) moment of force = force `xx` PERPENDICULAR distance of force from the wedge.
(iv) Find anti-clockwise and clockwise moments.
(v)PRINCIPLE of moments : sumof anti-clockwise moments = sum of clockwise moments.
(VI) 67.75 cmmark on scale.


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