1.

A uniform seesaw, 5m long, is supported at its centre. A boy weighing 40 kgf sits at a distance of 1 m from the centre of the seesaw. (i) To which class of lever does it belong ? (ii) Find where a girl of weight 20 kgf must sit on the seesaw so as the balance the weight of the boy.

Answer»

SOLUTION :(i) The seesaw has the fulcrum F at its centre i.e., between the load and the effort. It is a class I lever.
(Ii) To BALANCE the weight of the boy, LET the girl be sitting at a distance x METRE from the centre on the opposite side of the boy, then
Effort arm=x metre, load arm=1 metre,
Taking MOMENTS about F,
`40xx1=20xx x`
`therefore x=(40)/(20)=2m.`
Hence the girl must sit at a distance 2 m from the centre on the opposite side of the boy.


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